how many moles of nh3 are produced from 16 grams of n2 ?
N2 + 3H2 ==> 2NH3
16 g N2 = 16/28 mols = estimated 0.6.
0.6 x (2 mols NH3/1 molN2) = 0.6 x 2/1 = ?
To find the number of moles of NH3 produced from 16 grams of N2, we need to use the molar ratios from the balanced chemical equation.
The balanced equation for the reaction between N2 and NH3 is:
N2 + 3H2 -> 2NH3
From the balanced equation, we can see that for every 1 mole of N2, we get 2 moles of NH3.
To find the number of moles, we can use the following formula:
Number of moles = Mass / Molar mass
The molar mass of N2 is 28 g/mol, and the molar mass of NH3 is 17 g/mol.
Given that we have 16 grams of N2, we can calculate the number of moles:
Number of moles of N2 = Mass of N2 / Molar mass of N2
= 16 g / 28 g/mol
≈ 0.5714 mol
Therefore, for 16 grams of N2, approximately 0.5714 moles of NH3 will be produced.
To determine how many moles of NH3 are produced from 16 grams of N2, you need to follow these steps:
1. Write the balanced chemical equation for the reaction between N2 and NH3:
N2 + 3 H2 -> 2 NH3
2. Calculate the molar mass of N2 and NH3:
Molar mass of N2 = 28.02 g/mol
Molar mass of NH3 = 17.03 g/mol
3. Use the molar mass of N2 to convert grams of N2 to moles of N2:
Moles of N2 = grams of N2 / molar mass of N2
Moles of N2 = 16 g / 28.02 g/mol
4. Apply the stoichiometry of the balanced equation to determine the moles of NH3 produced:
According to the balanced equation, 1 mole of N2 reacts to produce 2 moles of NH3.
So, Moles of NH3 = Moles of N2 * (2 moles of NH3 / 1 mole of N2)
Now, let's calculate it:
Moles of N2 = 16 g / 28.02 g/mol ≈ 0.571 mol
Moles of NH3 = 0.571 mol * (2 mol NH3 / 1 mol N2) = 1.142 mol
Therefore, approximately 1.142 moles of NH3 are produced from 16 grams of N2.