Which correctly shows the area formula for a trapezoid, A=12h(b1+b2) , rearranged for the quantity of interest h?(1 point) Responses h=2Ab1+b2 h equals Start Fraction 2 upper A over b subscript 1 baseline plus b subscript 2 baseline End Fraction b1=2Ah−b2 b subscript 1 baseline dequals Start Fraction 2 upper A over h End Fraction minus b subscript 2 baseline h=b1+b22A h equals Start Fraction b subscript 1 baseline plus b subscript 2 baseline over 2 upper A End Fraction h=12A(b1+b2)
The correct rearranged formula for the quantity of interest h is:
h = (2A)/(b1 + b2)
To rearrange the trapezoid area formula, A=12h(b1+b2), for the quantity of interest h, we can follow these steps:
Step 1: Start with the given formula: A = 1/2h(b1 + b2)
Step 2: Multiply both sides of the equation by 2 to eliminate the fraction: 2A = h(b1 + b2)
Step 3: Divide both sides of the equation by (b1 + b2) to solve for h: h = 2A / (b1 + b2)
Therefore, the correct rearrangement for the quantity of interest h is: h = 2A / (b1 + b2)
To rearrange the area formula for a trapezoid, A = 1/2h(b1+b2), for the quantity of interest h, we need to isolate h on one side of the equation.
1. Start with the given formula for the area of a trapezoid: A = 1/2h(b1+b2).
2. Multiply both sides of the equation by 2 to eliminate the 1/2 fraction: 2A = h(b1+b2).
3. Divide both sides of the equation by (b1+b2) to isolate h: h = 2A / (b1+b2).
Therefore, the correct rearranged formula for the quantity of interest h is h = 2A / (b1+b2).