A fire engine’s water tank holds 750 gallons of water. If the pump removes 250 gallons of water in 5 minutes, what is the change in the amount of water in gallons in one minute?
The change in the amount of water in one minute is equal to the amount of water removed by the pump in 5 minutes divided by the number of minutes, or 250 gallons / 5 minutes = <<250/5=50>>50 gallons/minute. Answer: \boxed{50}.
To find the change in the amount of water in one minute, we need to determine how much water is being removed per minute.
Given that the pump removes 250 gallons of water in 5 minutes, we can find the amount of water removed per minute by dividing 250 gallons by 5 minutes:
250 gallons / 5 minutes = 50 gallons/minute.
Therefore, the change in the amount of water in one minute is 50 gallons.
To find the change in the amount of water in one minute, we need to determine how much water is being removed per minute.
Step 1: Calculate the amount of water being removed per minute.
We are given that the pump removes 250 gallons of water in 5 minutes. To find how much it removes in one minute, we can divide 250 gallons by 5 minutes:
250 gallons / 5 minutes = 50 gallons/minute
Therefore, the pump removes 50 gallons of water per minute.
Step 2: Determine the change in the amount of water in one minute.
Since the pump is removing water, the change in the amount of water in one minute is equal to the amount being removed per minute. In this case, it is 50 gallons.
So, the change in the amount of water in one minute is 50 gallons.