A swimming pool has a capacity of 10,000 gallons of water. If the drain removes 500 gallons of water in 10 minutes, what is the change in the amount of water in gallons in 1 minute?
If the drain removes 500 gallons of water in 10 minutes, the rate of water removal is 500 gallons/10 minutes = <<500/10=50>>50 gallons/minute.
Thus, the change in the amount of water in 1 minute is 50 gallons/minute. Answer: \boxed{50}.
To find the change in the amount of water in gallons in 1 minute, we need to determine the rate at which water is being drained.
Given:
- Capacity of the swimming pool: 10,000 gallons
- Drain removes: 500 gallons of water in 10 minutes
To find the drain rate per minute, we can divide the amount drained (500 gallons) by the time taken (10 minutes):
500 gallons / 10 minutes = 50 gallons/minute
Therefore, the change in the amount of water in gallons in 1 minute is 50 gallons.
To find the change in the amount of water in gallons in 1 minute, you need to calculate the rate at which water is being drained.
Given that the drain removes 500 gallons of water in 10 minutes, you can set up a proportion to find the drain rate per minute.
Let's assume "x" represents the amount of water drained in 1 minute.
So the proportion would look as follows:
500 gallons / 10 minutes = x gallons / 1 minute
To solve for "x," you can cross-multiply:
10 minutes * x gallons = 500 gallons * 1 minute
10x = 500
Now, divide both sides of the equation by 10 to isolate "x":
10x / 10 = 500 / 10
x = 50
Therefore, the drain removes 50 gallons of water in 1 minute.
To summarize, the change in the amount of water in 1 minute is 50 gallons.