A movie theater offers a special pricing for membership. The normal cost is $7.50 per ticket. The membership costs $5 per ticket but an initial fee of $25. After how many tickets are both options the same price?
Let's represent the total cost of tickets after x number of tickets by C(x).
For normal pricing, C(x) = 7.50x.
For membership pricing, C(x) = 5x + 25.
To find when both options are the same price, we set C(x) = C(x):
7.50x = 5x + 25
Subtracting 5x from both sides, we have:
2.50x = 25
Dividing both sides by 2.50, we get:
x = 10
Therefore, after purchasing 10 tickets, both options will cost the same price.
answer?
To determine the number of tickets at which both options have the same price, we need to set up an equation.
Let's represent the number of tickets as "x."
For the regular option, the cost per ticket is $7.50. Therefore, the total cost for x tickets would be 7.50 * x.
For the membership option, the cost per ticket is $5, but there is also an initial fee of $25. Therefore, the total cost for x tickets would be 5 * x + 25.
To find the number of tickets at which both options have the same price, we can set up the equation:
7.50 * x = 5 * x + 25
Now, let's solve for x:
7.50x = 5x + 25
7.50x - 5x = 25
2.50x = 25
x = 25 / 2.50
x = 10
So, after 10 tickets, both options will have the same price.
To find out the number of tickets at which both options are the same price, we need to set up an equation.
Let's denote the number of tickets as "x."
For the normal cost, the price per ticket is $7.50.
So, the cost for x tickets would be 7.50x.
For the membership cost, there is an initial fee of $25, and each ticket costs $5.
So, the cost for x tickets with the membership would be 25 + 5x.
To find the number of tickets where both options are the same price, we can set up an equation:
7.50x = 25 + 5x
Now, we can solve for x:
7.50x - 5x = 25
2.50x = 25
x = 25 / 2.50
x = 10
Therefore, at 10 tickets, both the normal cost and the membership cost will be the same.