Use the following solubility graph to answer the question below.

A solution of 10 grams KCl at 10 degrees Celsius is said to be:

a
unsaturated
b
saturated
c
supersaturated
Question 27

According to the solubility graph, at 10 degrees Celsius, the solubility of KCl is approximately 30 grams per 100 grams of water. Since the solution contains only 10 grams of KCl, it is unsaturated because it is below the solubility limit. Therefore, the answer is "a) unsaturated".

To determine whether a solution of 10 grams of KCl at 10 degrees Celsius is unsaturated, saturated, or supersaturated based on the given solubility graph, follow these steps:

1. Locate the point on the graph where the temperature of 10 degrees Celsius intersects with the solubility curve for KCl.

2. Determine the maximum amount of KCl that can dissolve in 100 grams of water at 10 degrees Celsius.

3. Compare the amount of KCl in the solution (10 grams) to the maximum solubility at that temperature.

Based on the comparison:
- If the amount of KCl in the solution is below the maximum solubility, the solution is unsaturated.
- If the amount of KCl in the solution is equal to the maximum solubility, the solution is saturated.
- If the amount of KCl in the solution is above the maximum solubility, the solution is supersaturated.

Please refer to the solubility graph to determine the specific answer for 10 grams of KCl at 10 degrees Celsius.

To answer the question, we need to interpret the given solubility graph. This graph typically shows the relationship between temperature and the maximum amount of solute (in this case, KCl) that can dissolve in a specific amount of solvent.

First, locate the point on the graph where the temperature is 10 degrees Celsius. Then, determine the solubility of KCl at this temperature.

If the line representing the solubility of KCl intersects with the point at 10 degrees Celsius and the amount of solute that can dissolve at this temperature is less than 10 grams, then the solution is unsaturated. This means that more KCl can still be dissolved.

If the line representing the solubility of KCl intersects with the point at 10 degrees Celsius and the amount of solute that can dissolve at this temperature is equal to 10 grams, then the solution is saturated. This means that the maximum amount of KCl that can dissolve at this temperature has already been reached.

If the line representing the solubility of KCl does not intersect with the point at 10 degrees Celsius, then the solution is supersaturated. This occurs when the solute (KCl) is present in a concentration that exceeds the maximum amount that should be able to dissolve at that temperature.

So, based on the given information, we need to locate the point on the solubility graph at 10 degrees Celsius and determine if the line representing the solubility of KCl intersects with this point and what the maximum solute concentration is at this temperature.