What is the percentage by mass of nitrogen in ammonium sulphate ?

The molecular formula of ammonium sulphate is (NH4)2SO4.

To find the percentage by mass of nitrogen in ammonium sulphate, we need to calculate the molar mass of the nitrogen and the molar mass of the whole compound.

Molar mass of nitrogen (N) = 14.01 g/mol
Molar mass of sulphur (S) = 32.07 g/mol
Molar mass of hydrogen (H) = 1.008 g/mol
Molar mass of oxygen (O) = 16.00 g/mol

Total molar mass of (NH4)2SO4:
2(NH4) = 2(1.008 g/mol) + 4(1.008 g/mol) = 18.015 g/mol
SO4 = 32.07 g/mol + 4(16.00 g/mol) = 96.06 g/mol

Total molar mass of (NH4)2SO4 = 18.015 g/mol + 96.06 g/mol = 114.075 g/mol

Now, to calculate the percentage by mass of nitrogen in ammonium sulphate:

Percentage by mass of nitrogen = (molar mass of nitrogen / molar mass of (NH4)2SO4) × 100
= (14.01 g/mol / 114.075 g/mol) × 100 ≈ 12.26%

Therefore, the percentage by mass of nitrogen in ammonium sulphate is approximately 12.26%.

To calculate the percentage by mass of nitrogen in ammonium sulfate, we need to consider the molecular formula of ammonium sulfate (NH4)2SO4 and the molar masses of nitrogen and ammonium sulfate.

Step 1: Calculate the molar mass of ammonium sulfate
The molar mass of (NH4)2SO4 can be calculated by summing the molar masses of all its atoms:
(NH4)2SO4
= [2(N) + 8(H)] + [1(S) + 4(O)]
= (2 * 14.01 g/mol) + (8 * 1.008 g/mol) + (1 * 32.07 g/mol) + (4 * 16.00 g/mol)
= 132.14 g/mol

Step 2: Calculate the molar mass of nitrogen
The molar mass of nitrogen is 14.01 g/mol.

Step 3: Determine the mass of nitrogen in ammonium sulfate
Since there are two nitrogen atoms in one molecule of ammonium sulfate, we need to calculate the mass of nitrogen for only one nitrogen atom:
(14.01 g/mol) * (2 / 132.14 g/mol) = 0.212 g

Step 4: Calculate the percentage by mass of nitrogen
To find the percentage by mass of nitrogen in ammonium sulfate, divide the mass of nitrogen by the molar mass of ammonium sulfate and multiply by 100:
(0.212 g / 132.14 g) * 100 = 0.16%

Therefore, the percentage by mass of nitrogen in ammonium sulfate is approximately 0.16%.

To calculate the percentage by mass of nitrogen in ammonium sulfate, we need to know the mass of nitrogen in relation to the total mass of ammonium sulfate.

First, find the molar mass of ammonium sulfate (NH4)2SO4:

- The atomic mass of nitrogen (N) is approximately 14.01 g/mol.
- The atomic mass of hydrogen (H) is approximately 1.01 g/mol.
- The atomic mass of sulfur (S) is approximately 32.07 g/mol.
- The atomic mass of oxygen (O) is approximately 16.00 g/mol.

Ammonium (NH4) consists of one nitrogen atom and four hydrogen atoms, so its molar mass is:

(1 × atomic mass of nitrogen) + (4 × atomic mass of hydrogen)
= (1 × 14.01 g/mol) + (4 × 1.01 g/mol)
= 14.01 g/mol + 4.04 g/mol
= 18.05 g/mol

Sulfate (SO4) consists of one sulfur atom and four oxygen atoms, so its molar mass is:

(1 × atomic mass of sulfur) + (4 × atomic mass of oxygen)
= (1 × 32.07 g/mol) + (4 × 16.00 g/mol)
= 32.07 g/mol + 64.00 g/mol
= 96.07 g/mol

Now, calculate the molar mass of ammonium sulfate:

(2 × molar mass of ammonium) + molar mass of sulfate
= (2 × 18.05 g/mol) + 96.07 g/mol
= 36.10 g/mol + 96.07 g/mol
= 132.17 g/mol

Next, find the molar mass of nitrogen in ammonium sulfate:

(1 × molar mass of nitrogen) / molar mass of ammonium sulfate
= (1 × 14.01 g/mol) / 132.17 g/mol
= 14.01 g/mol / 132.17 g/mol
≈ 0.106

Finally, calculate the percentage by mass of nitrogen in ammonium sulfate by multiplying the molar mass of nitrogen by 100:

0.106 × 100 ≈ 10.6%

Therefore, the percentage by mass of nitrogen in ammonium sulfate is approximately 10.6%.