Cedric plans to ride his bicycle 2 miles to a park and then ride several times around a loop in the park that is 5 miles long. Then he'll ride the same way home. He wants to ride a total of at least 19 miles. The inequality 5t+4>19 models this situation, where t is the number of times Cedric rides around the loop. Solve the inequality. How many times does Cedric need to ride around the loop? A. 3 or more times B. At most 4 C. At most 3 times D. 4 or more times
To solve the inequality 5t + 4 > 19, we can begin by subtracting 4 from both sides, which gives 5t > 15. Then, we can divide both sides by 5 to solve for t, which gives t > 3. Cedric needs to ride the loop at least 4 times in order to ride a total of at least 19 miles. Therefore, the answer is D. 4 or more times.
To solve the inequality 5t+4 > 19, we first subtract 4 from both sides of the inequality, as follows:
5t+4-4 > 19-4
5t > 15
Next, we divide both sides of the inequality by 5 to solve for t:
(5t)/5 > 15/5
t > 3
Therefore, Cedric needs to ride around the loop at least 4 or more times, which is represented by option D.
To solve the inequality 5t + 4 > 19, we can follow these steps:
1. Subtract 4 from both sides of the inequality:
5t + 4 - 4 > 19 - 4
5t > 15
2. Divide both sides of the inequality by 5 to isolate t:
5t/5 > 15/5
t > 3
The solution to the inequality is t > 3. This means Cedric needs to ride around the loop at least 4 times (since t must be a positive whole number).
So, the correct answer is D. 4 or more times.