Calculate the number of moles of sodium hydroxide needed to neutralise the hydrochloric acid in the Erlenmeyer
Unfortunately, the question is incomplete, as it does not provide the amounts or concentrations of hydrochloric acid and sodium hydroxide present in the Erlenmeyer flask. Could you please provide this information?
To calculate the number of moles of sodium hydroxide needed to neutralize hydrochloric acid in the Erlenmeyer flask, you'll need the concentration and volume of the hydrochloric acid.
If you have the molarity (M) of the hydrochloric acid solution, you can use the following formula:
moles of hydrochloric acid = concentration (M) × volume (L)
Once you know the moles of hydrochloric acid, you can determine the number of moles of sodium hydroxide required by noting that the balanced chemical equation between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:
HCl + NaOH → NaCl + H2O
From the balanced equation, you can see that one mole of hydrochloric acid will react with one mole of sodium hydroxide. Therefore, the moles of sodium hydroxide required will be the same as the moles of hydrochloric acid.
To calculate the number of moles of sodium hydroxide (NaOH) needed to neutralize hydrochloric acid (HCl) in the Erlenmeyer flask, you will need to know the molarity (concentration) of the HCl.
Here's the step-by-step process to calculate the number of moles:
1. Determine the balanced chemical equation for the reaction between NaOH and HCl:
NaOH + HCl → NaCl + H2O
2. Identify the stoichiometry of the reaction, which tells you the mole ratio between the reactants. In this case, the stoichiometry is 1:1, meaning for every 1 mole of NaOH, you need 1 mole of HCl to achieve a complete reaction.
3. Measure the volume of the HCl solution in the Erlenmeyer flask.
4. Determine the molarity (concentration) of the HCl solution. Molarity is expressed as moles of solute per liter of solution (mol/L or M).
5. Multiply the volume (in liters) of the HCl solution by its molarity to obtain the number of moles of HCl.
6. Use the stoichiometry from step 2 to determine the number of moles of NaOH needed. If the stoichiometry is 1:1, then the number of moles of NaOH required will be the same as the moles of HCl.
Let's say that the volume of the HCl solution is 0.050 L and its molarity is 0.250 M:
Number of moles of HCl = 0.050 L * 0.250 mol/L
= 0.0125 mol HCl
Therefore, you would need 0.0125 moles of NaOH to neutralize the hydrochloric acid in the Erlenmeyer flask.