solve the following word problem. the air temperature at 9 am is -5.8 degrees Celsius the air temperature at noon is -1.6 degrees Celsius. what is the change in the temperature during these three hours? write and solve an equation tos how your answer. then explain what your answer means
To find the change in temperature during these three hours, we need to subtract the air temperature at 9 am from the air temperature at noon.
The equation to represent this is: Change in Temperature = Temperature at Noon - Temperature at 9 am.
Substituting the given values, we have: Change in Temperature = (-1.6) - (-5.8).
Simplifying, we get: Change in Temperature = -1.6 + 5.8.
Calculating further, we have: Change in Temperature = 4.2 degrees Celsius.
Therefore, the change in temperature during these three hours is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from 9 am to noon.
To find the change in temperature during the three hours from 9 am to noon, we can subtract the initial temperature from the final temperature.
Initial temperature at 9 am: -5.8 degrees Celsius
Final temperature at noon: -1.6 degrees Celsius
Change in temperature = Final temperature - Initial temperature
Change in temperature = (-1.6) - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius
The equation used is:
Change in temperature = -1.6 - (-5.8)
= -1.6 + 5.8
= 4.2
This means that the temperature increased by 4.2 degrees Celsius during the three hours.
To find the change in temperature during these three hours, we need to calculate the difference between the air temperature at 9 am and the air temperature at noon.
First, let's define a variable for the change in temperature. Let's call it ΔT.
We know that the air temperature at 9 am is -5.8 degrees Celsius, and the air temperature at noon is -1.6 degrees Celsius. Therefore, the change in temperature can be represented as:
ΔT = (-1.6) - (-5.8)
Simplifying this equation, we have:
ΔT = -1.6 + 5.8
Adding the values together, we find:
ΔT = 4.2
Therefore, the change in temperature during these three hours is 4.2 degrees Celsius.
The positive ΔT tells us that the temperature increased from 9 am to noon. In this case, the increase was 4.2 degrees Celsius.