write an equation of the ine, inpoint slope form, that pases through the given points and has the given slope
(8,-8); slope:3
The point-slope form of a linear equation is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
Using the given slope (m = 3) and the point (8, -8), the equation in point-slope form can be written as:
y - (-8) = 3(x - 8)
Simplifying,
y + 8 = 3x - 24
Thus, the equation of the line in point-slope form is:
y = 3x - 32
To write the equation of a line in point-slope form, which is y - y1 = m(x - x1), where (x1, y1) are the coordinates of a point on the line, and m is the slope, we can use the given information.
Given points: (8, -8)
Slope: 3
Let's substitute the values into the equation to find the equation of the line:
y - (-8) = 3(x - 8)
Simplifying:
y + 8 = 3x - 24
Therefore, the equation of the line in point-slope form that passes through the point (8, -8) and has a slope of 3 is y + 8 = 3x - 24.
To write the equation of a line in point-slope form, you need the coordinates of a point on the line and the slope of the line. In this case, the point given is (8, -8), and the slope is 3.
The point-slope form is given by: y - y₁ = m(x - x₁), where (x₁, y₁) are the coordinates of the point and m is the slope.
So, plugging in the values we have, we get:
y - (-8) = 3(x - 8)
Simplifying the equation:
y + 8 = 3x - 24
Finally, you can rewrite it in the standard form:
3x - y = 32
Therefore, the equation of the line, in point-slope form, that passes through the point (8, -8) and has a slope of 3 is 3x - y = 32.