Use the following setup and given equation to find the solution:
1st integer = x
2nd integer = x + 2
3rd integer = x + 4
The sum of the integers is : x + x + 2 + x + 4 = 222
. What is the 2nd integer?
Responses
64
64
111
111
222
222
74
74
To find the solution, let's set up the equation:
1st integer (x) + 2nd integer (x + 2) + 3rd integer (x + 4) = 222
Combining like terms, we have:
3x + 6 = 222
Subtracting 6 from both sides, we get:
3x = 216
Dividing both sides by 3, we find:
x = 72
Now, to find the 2nd integer, substitute the value of x back into the equation:
2nd integer = x + 2 = 72 + 2 = 74.
Therefore, the 2nd integer is 74.
To find the solution, we need to solve the equation:
x + (x + 2) + (x + 4) = 222
Simplifying this equation, we get:
3x + 6 = 222
Next, we can subtract 6 from both sides of the equation:
3x = 216
Then, we divide both sides of the equation by 3 to solve for x:
x = 72
Now that we know x = 72, we can find the value of the second integer by substituting x back into the expression:
x + 2 = 72 + 2 = 74
Therefore, the second integer in this setup is 74.