The sum of three consecutive even integers (3 even integers in a row) is 120.
Use the following setup and given equation to find your solution:
1st integer = x
2nd integer = x+2
3rd integer = x+4
Equation: x+(x+2)+(x+4)=120
Solve the equation above. What is the largest of the three integers?
42
38
44
38, 42, 44
To solve the given equation, we need to combine like terms and solve for x:
x + (x+2) + (x+4) = 120
Combine like terms:
3x + 6 = 120
Subtract 6 from both sides:
3x = 114
Divide both sides by 3:
x = 38
The largest of the three integers is x+4:
38 + 4 = 42
Therefore, the largest of the three integers is 42.
To solve the given equation x + (x+2) + (x+4) = 120, we can combine like terms and simplify:
3x + 6 = 120
Next, we can isolate the variable x by subtracting 6 from both sides of the equation:
3x = 114
Then, we divide both sides by 3 to solve for x:
x = 38
So, the first integer is 38. The second integer would be x + 2, which is 38 + 2 = 40. Lastly, the third integer is x + 4, which is 38 + 4 = 42.
Therefore, the largest of the three integers is 42.