A fire engine's water tank holds 750 gallons of water. If the pump removes 250 gallons of water in 5 minutes, what is the change in the amount of water in gallons in 1 minute? (1 point)
50
15
-50
-15
The pump removes 250 gallons of water in 5 minutes, so in 1 minute, it removes 250/5 = <<250/5=50>>50 gallons of water.
The change in the amount of water is -50 gallons, so the answer is -50. Answer: \boxed{-50}.
Solve the following word problem. A fish is swimming at −10.8 meters, or 10.8 meters below sea level. Every 2 minutes it descends another 1.5 meters. How long will it take for the fish to reach a depth of −37.8 meters? Show your work and write a sentence to explain what your answer means.
To find the change in the amount of water in 1 minute, divide the amount of water removed in 5 minutes (250 gallons) by the number of minutes (5):
250 gallons / 5 minutes = 50 gallons/minute
Therefore, the change in the amount of water in gallons in 1 minute is 50.
To find the change in the amount of water in one minute, you need to calculate the rate at which the pump removes water from the tank.
Given that the pump removes 250 gallons of water in 5 minutes, you can find the rate at which water is being removed by dividing the amount of water removed (250 gallons) by the time taken (5 minutes):
Rate = Amount of water removed / Time taken
Rate = 250 gallons / 5 minutes = 50 gallons per minute
So, the pump removes water from the tank at a rate of 50 gallons per minute. However, you're asked for the change in the amount of water in one minute, which means you need to find this rate as a decrease in the amount of water in the tank.
Since the pump removes water from the tank, the change in the amount of water in one minute will be negative, indicating a decrease.
Therefore, the correct answer is -50 gallons.