What is the least integer whose square root is an irrational number between 5 and 7
6
13
26
25
The least integer whose square root is an irrational number between 5 and 7 is 26.
To find the least integer whose square root is an irrational number between 5 and 7, we need to check the squares of integers in that range.
Squaring 6 gives us 36, which is greater than 25 (the square of a whole number) but less than 49 (the square of 7).
Squaring 13 gives us 169, which is greater than 49.
Squaring 26 gives us 676, which is greater than 49.
Squaring 25 gives us 625, which is between 5^2 and 7^2.
Therefore, the least integer whose square root is an irrational number between 5 and 7 is 25.
To find the least integer whose square root is an irrational number between 5 and 7, we need to test the square roots of integers within this range.
First, we can check the integer 6. The square root of 6 is approximately 2.449, which is not within the desired range of 5 to 7.
Next, let's check the integer 13. The square root of 13 is approximately 3.605, which also does not fall between 5 and 7.
Moving on, let's examine the integer 26. The square root of 26 is approximately 5.099, which falls within the desired range of 5 to 7. However, since the question asks for the "least" integer, we need to continue searching.
Lastly, we check the integer 25. The square root of 25 is 5, which falls within the desired range of 5 to 7.
So, out of the given options, the least integer whose square root is an irrational number between 5 and 7 is 25.