The Jurassic Zoo charges $9 for each adult admission and $7 for each child. The total bill for the 80 people from a school trip was $602. How many adults and how many children went to the zoo?
Let's assume the number of adults is x and the number of children is y.
The cost for adults is $9 per person, so the total cost for adults is 9x.
The cost for children is $7 per person, so the total cost for children is 7y.
The total bill for the 80 people who went to the zoo is $602:
9x + 7y = 602
We also know that there were a total of 80 people at the zoo:
x + y = 80
We can solve this system of equations to find the values of x and y.
Let's solve the second equation for x:
x = 80 - y
Substituting this value of x in the first equation, we get:
9(80 - y) + 7y = 602
Simplifying,
720 - 9y + 7y = 602
-2y = 602 - 720
-2y = -118
Dividing both sides by -2, we get:
y = (-118) / (-2) = 59
Substituting this value of y in the equation x = 80 - y, we get:
x = 80 - 59 = 21
So, there were 21 adults and 59 children at the zoo.
Let's assume the number of adults who went to the zoo is 'a' and the number of children is 'c'.
According to the given information, the total bill for the school trip was $602.
The cost of each adult ticket is $9, and the cost of each child ticket is $7.
So, we can write the following equations:
Equation 1: a + c = 80 (since the total number of people is 80)
Equation 2: 9a + 7c = 602 (since the total bill amount is $602)
We can solve this system of equations to find the values of 'a' and 'c'.
First, let's rearrange Equation 1 to express 'a' in terms of 'c':
a = 80 - c
Substitute this value of 'a' into Equation 2:
9(80 - c) + 7c = 602
720 - 9c + 7c = 602
-2c = 602 - 720
-2c = -118
c = (-118)/(-2)
c = 59
Now, substitute the value of 'c' back into Equation 1 to find 'a':
a + 59 = 80
a = 80 - 59
a = 21
Therefore, there were 21 adults and 59 children who went to the zoo.