The Jurassic Zoo charges $13 for each adult admission and $4 for each child. The total bill for the 87 people from a school trip was $600. How many adults and how many children went to the zoo?
Let's assume the number of adults is x and the number of children is y.
According to the given information, the total number of people who went to the zoo is 87, so we have x + y = 87 (equation 1).
We also know that the total bill for the group was $600, so we have 13x + 4y = 600 (equation 2).
Now, we can use these two equations to solve for x and y. We can solve equation 1 for x by subtracting y from both sides: x = 87 - y.
Substituting the value of x in equation 2, we have 13(87-y) + 4y = 600.
Distributing and simplifying the equation, we get 1131 - 13y + 4y = 600.
Combining like terms, we get -9y + 1131 = 600.
Subtracting 1131 from both sides, we have -9y = -531.
Dividing both sides by -9, we get y = 59.
Substituting the value of y back into equation 1, we have x + 59 = 87.
Subtracting 59 from both sides, we get x = 28.
Therefore, there were 28 adults and 59 children who went to the zoo.
Let's assume the number of adults who went to the zoo is A, and the number of children is C.
According to the problem, the cost for each adult ticket is $13 and each child ticket is $4. We can create the following equation based on the total bill:
13A + 4C = 600 [Equation 1]
We also know that the total number of people who went to the zoo is 87. So, we can create another equation based on the total number of people:
A + C = 87 [Equation 2]
Now, we can solve this system of equations using substitution or elimination method.
Let's solve using substitution:
From Equation 2, we can solve it for C:
C = 87 - A
Substituting this value of C in Equation 1:
13A + 4(87 - A) = 600
13A + 348 - 4A = 600
9A = 600 - 348
9A = 252
A = 252 / 9
A = 28
Substituting the value of A back into Equation 2:
28 + C = 87
C = 87 - 28
C = 59
Therefore, there were 28 adults and 59 children who went to the zoo.
To solve this problem, we can set up a system of equations based on the given information. Let's assume the number of adults attending the zoo is represented by the variable 'a', and the number of children attending is represented by the variable 'c'.
From the first piece of information, we know that the cost of each adult admission is $13. So, the total cost of adult admissions is 13a.
From the second piece of information, we know that the cost of each child admission is $4. Thus, the total cost of child admissions is 4c.
Since the total bill for the school trip was $600, we can write the equation 13a + 4c = 600.
We also know that the total number of people attending the zoo was 87. So, we have the equation a + c = 87.
Now, we have a system of equations:
13a + 4c = 600 (equation 1)
a + c = 87 (equation 2)
We can solve this system of equations using substitution or elimination.
Let's solve using substitution:
From equation 2, we can express a in terms of c as a = 87 - c.
Substituting this value in equation 1, we get:
13(87 - c) + 4c = 600
Expanding, we have:
1131 - 13c + 4c = 600
Combining like terms, we get:
-9c = -531
Dividing by -9, we have:
c = 59
Substituting c = 59 back into equation 2, we get:
a + 59 = 87
Subtracting 59 from both sides, we have:
a = 87 - 59
a = 28
Therefore, 28 adults and 59 children went to the zoo.