16. An aluminum block has a starting temperature of 300oC. The block is placed into 200 milliliters of water, which has a temperature of 20oC. What heat transfer will occur?(1 point)
Responses
Heat will flow from the block to the water until both substances have a temperature between 20 degrees Celsius and 300 degrees Celcius.
Heat will flow from the block to the water until both substances have a temperature between 20 degrees Celsius and 300 degrees Celcius.
Heat will flow from the block to the water until both have a temperature of 300oC.
Heat will flow from the block to the water until both have a temperature of 300oC.
Heat will flow from the block to the water until both substances have the same temperature as their container.
Heat will flow from the block to the water until both substances have the same temperature as their container.
Heat will flow from the block to the water until both substances have a temperature of 20 degrees Celcius.
Heat will flow from the block to the water until both substances have the same temperature as their container.
Heat will flow from the block to the water until both substances have the same temperature as their container.
Heat will flow from the block to the water until both substances have the same temperature. To find the amount of heat transfer, we can use the heat transfer equation:
Q = mcΔT
where Q is the heat transfer, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
First, we need to calculate the mass of the water. Since we have the volume of water in milliliters, we need to convert it to grams:
Density of water = 1 g/mL
Volume of water = 200 mL
Mass of water = Density x Volume
= 1 g/mL x 200 mL
= 200 g
Next, we need to determine the specific heat capacity of aluminum and water. The specific heat capacity of aluminum is 0.9 J/g°C, and the specific heat capacity of water is 4.18 J/g°C.
Now, let's calculate the heat transfer.
ΔT = final temperature - initial temperature
For the final temperature, we need to find the temperature at which both the block and water reach thermal equilibrium. This occurs when they have the same temperature.
Qaluminum = maluminum x caluminum x ΔTaluminum
Qwater = mwater x cwater x ΔTwater
Since the final temperature will be the same for both aluminum and water, we can set their heat transfer equations equal to each other:
maluminum x caluminum x ΔTaluminum = mwater x cwater x ΔTwater
Now, we can solve for the heat transfer, Q:
Q = maluminum x caluminum x ΔTaluminum
= mwater x cwater x ΔTwater