An aluminum block has a starting temperature of 300oC. The block is placed into 200 milliliters of water, which has a temperature of 20oC. What heat transfer will occur?
To calculate the heat transfer that will occur between the aluminum block and the water, we can use the formula:
q = mcΔT
Where:
q is the heat transfer
m is the mass of the substance (water in this case)
c is the specific heat capacity of the substance (water in this case)
ΔT is the change in temperature
First, we need to find the mass of the water. We know that the volume of the water is 200 milliliters. The density of water is 1 gram per milliliter. Therefore, the mass of the water can be calculated as:
mass = volume × density
mass = 200 ml × 1 g/ml
mass = 200 g
Next, we need to find the specific heat capacity of water. The specific heat capacity of water is 4.186 Joules per gram per degree Celsius (J/g°C).
Using the formula, we can find the heat transfer:
q = mcΔT
q = (200 g) × (4.186 J/g°C) × (300°C - 20°C)
q = (200 g) × (4.186 J/g°C) × (280°C)
q ≈ 234,152 J
Therefore, the heat transfer that will occur between the aluminum block and the water is approximately 234,152 Joules.
To determine the heat transfer that will occur between the aluminum block and the water, we can use the equation
Q = m * c * ΔT
Where:
Q = Heat transfer
m = mass
c = specific heat capacity
ΔT = change in temperature
Let's calculate the heat transfer step-by-step:
Step 1: Calculate the mass of water
The density of water is approximately 1 g/ml. Therefore, the mass of 200 milliliters of water can be calculated as follows:
mass of water = volume of water * density of water
mass of water = 200 ml * 1 g/ml
mass of water = 200 g
Step 2: Calculate the change in temperature
The change in temperature is the final temperature minus the initial temperature. In this case:
ΔT = final temperature - initial temperature
ΔT = 20°C - (-300°C)
ΔT = 320°C
Step 3: Determine the specific heat capacity of water
The specific heat capacity of water is approximately 4.18 J/g·°C.
Step 4: Calculate the heat transfer
Using the formula Q = m * c * ΔT, we can substitute the values found:
Q = 200 g * 4.18 J/g·°C * 320°C
Q = 267,200 J
Therefore, the heat transfer between the aluminum block and the water will be 267,200 Joules (J).
To calculate the heat transfer, you need to use the formula:
Q = mcΔT
Where:
Q is the heat transfer (in Joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/g·°C)
ΔT is the change in temperature (in °C)
First, let's calculate the mass of the water. The density of water is approximately 1 gram per milliliter. So, 200 milliliters of water would have a mass of 200 grams.
Now, let's calculate the change in temperature for the aluminum block. The starting temperature of the block is 300°C, and the temperature of the water is 20°C. So, the change in temperature (ΔT) would be:
ΔT = T(final) - T(initial)
= 20°C - 300°C
= -280°C
Since the temperature change is negative, it means the aluminum block will lose heat to the water.
Next, we need the specific heat capacity of aluminum. The specific heat capacity of aluminum is approximately 0.897 J/g·°C.
Now, we can substitute the values into the formula:
Q = mcΔT
= (mass of aluminum)(specific heat capacity of aluminum)(change in temperature of aluminum)
To calculate the heat transfer, we need to know the mass of the aluminum block. If you have the mass, you can substitute it into the equation to get the value of Q in Joules.