A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2 by using the formula 75−16t2, where t is time in seconds.
To find the number of feet the diver is above the ocean in 2 seconds, we need to substitute t=2 into the formula 75-16t^2.
Plugging t=2 into the formula, we get:
75 - 16(2^2) = 75 - 16(4) = 75 - 64 = 11.
Therefore, the diver is 11 feet above the ocean in 2 seconds.
To find the number of feet the diver is above the ocean in 2 seconds, we will substitute t=2 into the formula 75−16t2.
Replacing t with 2 in the formula:
75 - 16(2)^2
Simplifying the formula:
75 - 16 * 4
75 - 64
= 11
Therefore, the diver is 11 feet above the ocean in 2 seconds.
To find the number of feet the diver is above the ocean in 2 seconds, we need to substitute t=2 into the given formula 75 - 16t^2.
Step 1: Substitute t=2 into the formula:
75 - 16(2)^2
Step 2: Simplify the expression inside the parentheses:
75 - 16(4)
Step 3: Multiply:
75 - 64
Step 4: Subtract:
11
Therefore, the diver is 11 feet above the ocean after 2 seconds.