Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. explain
To find the change in temperature, we need to subtract the temperature at 9 a.m. from the temperature at noon.
Let X be the change in temperature.
The equation to represent this is: −1.6 degrees Celsius - (−5.8 degrees Celsius) = X.
Simplifying this equation gives: −1.6 degrees Celsius + 5.8 degrees Celsius = X.
The sum of -1.6 degrees Celsius and 5.8 degrees Celsius is 4.2 degrees Celsius.
Therefore, the change in temperature during these three hours is 4.2 degrees Celsius.
To calculate the change in temperature during the three-hour period, we need to subtract the initial temperature (9 a.m.) from the final temperature (noon). Let's define "T" as the change in temperature.
The initial temperature at 9 a.m. is -5.8 degrees Celsius.
The final temperature at noon is -1.6 degrees Celsius.
So, to calculate the change in temperature, we subtract the initial temperature from the final temperature:
T = final temperature - initial temperature
T = -1.6°C - (-5.8°C)
T = -1.6°C + 5.8°C
T = 4.2°C
Therefore, the change in temperature during these three hours is an increase of 4.2 degrees Celsius.