What is the slope and the y-intercept of the equation 9+272x=−32y. Write the y-intercept as an ordered pair.(1 point)
To find the slope and y-intercept of the equation 9+272x=−32y, we need to rewrite the equation in slope-intercept form, which has the form y = mx + b, where m is the slope and b is the y-intercept.
Starting with the given equation:
9 + 272x = -32y,
Let's solve for y by isolating it on one side:
272x = -32y - 9.
Divide both sides by -32:
y = (-272/32)x - 9/(-32).
Simplifying the equation further:
y = (-34/4)x + 9/32,
y = -8.5x + 9/32.
Now we can see that the slope of the equation is -8.5 and the y-intercept (b) is 9/32.
Writing the y-intercept as an ordered pair (0, b), the y-intercept is (0, 9/32).
To find the slope and y-intercept of the equation 9 + 272x = -32y, we need to rewrite the equation in slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.
To do this, we can rearrange the given equation as follows:
9 + 272x = -32y
Divide both sides by -32 to isolate y:
(-32y) / -32 = (9 + 272x) / -32
Simplifying further:
y = (-9/32) - (17/8)x
Comparing this equation to y = mx + b, we can determine that the slope (m) is -17/8 and the y-intercept (b) is -9/32.
To write the y-intercept as an ordered pair, we can substitute the x-coordinate as 0 into the equation and solve for y:
y = (-9/32) - (17/8)(0)
y = -9/32
Therefore, the y-intercept can be written as the ordered pair (0, -9/32).