What is the slope and the y -intercept of the equation 9+27/2x=−32y . Write the y -intercept as an ordered pair.(1 point)
What is the slope and the y -intercept of the equation 9+27/2x=−3/2y . Write the y -intercept as an ordered pair.
To determine the slope and y-intercept of the equation 9 + 27/2x = -32y, we can rewrite the equation in slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept.
First, let's isolate y on one side of the equation:
9 + 27/2x = -32y
To isolate -y, divide both sides of the equation by -32:
(9 + 27/2x)/-32 = y
-(9 + 27/2x)/32 = y
-9/32 - 27/64x = y
So, the equation in slope-intercept form is y = -27/64x - 9/32.
Comparing this equation to y = mx + b, we can see that the slope (m) is -27/64, and the y-intercept (b) is -9/32.
To write the y-intercept as an ordered pair, we substitute x = 0 into the equation:
y = -27/64(0) - 9/32
y = -9/32
Therefore, the y-intercept is (0, -9/32).
To determine the slope and y-intercept of the equation 9 + 27/2x = -3/2y, we need to rewrite the equation in slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept.
First, let's isolate y on one side of the equation:
9 + 27/2x = -3/2y
To isolate y, divide both sides of the equation by -3/2:
(9 + 27/2x) / (-3/2) = y
(9 + 27/2x) * (-2/3) = y
Simplifying the expression on the right side:
y = -2(9 + 27/2x) / 3
y = (-18 - 54/2x) / 3
y = (-18 - 27x) / 3
y = -6 - 9x
So, the equation in slope-intercept form is y = -9x - 6.
Comparing this equation to y = mx + b, we can see that the slope (m) is -9, and the y-intercept (b) is -6.
To write the y-intercept as an ordered pair, we substitute x = 0 into the equation:
y = -9(0) - 6
y = -6
Therefore, the y-intercept is (0, -6).
To find the slope and the y-intercept of the equation, we need to rewrite the equation in slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept.
Starting with the given equation:
9 + (27/2)x = -32y
First, isolate y by dividing both sides by -32:
(-32y) = (9 + (27/2)x)
y = -9/32 - (27/64)x
Now, we can see that the equation is in slope-intercept form, with a slope of -27/64 and a y-intercept of -9/32.
So, the slope (m) is -27/64 and the y-intercept (b) is -9/32.
To represent the y-intercept as an ordered pair, we use the point (0, -9/32).
To find the slope and y-intercept of the equation 9 + 27/2x = -32y, we first need to rearrange the equation into slope-intercept form, which has the form y = mx + b, where m is the slope and b is the y-intercept.
Let's start by isolating y on one side of the equation:
9 + 27/2x = -32y
Divide both sides of the equation by -32:
(9 + 27/2x) / -32 = y
Simplifying further:
(9/-32) + (27/2x) / -32 = y
Now, let's simplify the fractions:
-9/32 - (27/64)x = y
So, the equation is now in the form y = (-27/64)x - 9/32.
The slope of the equation is the coefficient of x, which in this case is -27/64.
The y-intercept is the value of y when x = 0. Substitute x = 0 into the equation to find the y-intercept:
y = (-27/64)(0) - 9/32
y = -9/32
Therefore, the y-intercept is (-9/32, 0).