A student has some $1 bills and $5 bills in his wallet. He has a total of 15 bills that are worth $47. How many of each type of bill does he have?
Let's assume the student has x $1 bills and y $5 bills.
We know that the student has a total of 15 bills, so we can write the equation x + y = 15. (Equation 1)
We also know that the total amount of money in the wallet is $47, so we can write the equation 1x + 5y = 47. (Equation 2)
Now we can solve the system of equations using substitution or elimination.
Substitution:
From Equation 1, we can rewrite x = 15 - y.
Substituting this value of x into Equation 2:
1(15 - y) + 5y = 47
15 - y + 5y = 47
15 + 4y = 47
4y = 47 - 15
4y = 32
y = 32/4
y = 8
Substituting this value of y back into x = 15 - y:
x = 15 - 8
x = 7
Therefore, the student has 7 $1 bills and 8 $5 bills.
Let's say the number of $1 bills the student has is represented by "x", and the number of $5 bills he has is represented by "y".
From the given information, we can form two equations:
1. The total number of bills: x + y = 15
2. The total value of the bills: $1x + $5y = $47
To solve these equations, we can use substitution or elimination methods. Let's use the substitution method:
We can rewrite equation 1 as x = 15 - y.
Substituting this value of x into equation 2:
$1(15 - y) + $5y = $47
Simplifying:
15 - y + 5y = 47
15 + 4y = 47
4y = 47 - 15
4y = 32
y = 32/4
y = 8
Substituting the value of y back into equation 1:
x + 8 = 15
x = 15 - 8
x = 7
Therefore, the student has 7 $1 bills and 8 $5 bills.