Jordan has three bills in her wallet. They might be any combination of $5,$10, and/or $20 bills. a) Fill in the organized list to show ll the possible combination of bills.
You have 3 items
The number of subsets is 2^3 = 8
This includes the null set, that is, none of the bills
If you want to exclude it, there would be 7 cases
To find all the possible combinations of bills in Jordan's wallet, we can use a method called "listing" or "listing systematically." We will examine each possible combination by considering all possible options.
We know that Jordan has three bills, and each bill can be either $5, $10, or $20. To systematically list all the possibilities, we can follow these steps:
Step 1: Start by listing the options for the first bill:
- Bill 1: $5
- Bill 1: $10
- Bill 1: $20
Step 2: For each option in Step 1, list the possibilities for the second bill:
- If Bill 1 is $5, options for Bill 2: $5, $10, $20
- If Bill 1 is $10, options for Bill 2: $5, $10, $20
- If Bill 1 is $20, options for Bill 2: $5, $10, $20
Step 3: For each combination from Step 2, list the possibilities for the third bill:
- If Bill 1 is $5 and Bill 2 is $5, options for Bill 3: $5, $10, $20
- If Bill 1 is $5 and Bill 2 is $10, options for Bill 3: $5, $10, $20
- If Bill 1 is $5 and Bill 2 is $20, options for Bill 3: $5, $10, $20
- If Bill 1 is $10 and Bill 2 is $5, options for Bill 3: $5, $10, $20
- If Bill 1 is $10 and Bill 2 is $10, options for Bill 3: $5, $10, $20
- If Bill 1 is $10 and Bill 2 is $20, options for Bill 3: $5, $10, $20
- If Bill 1 is $20 and Bill 2 is $5, options for Bill 3: $5, $10, $20
- If Bill 1 is $20 and Bill 2 is $10, options for Bill 3: $5, $10, $20
- If Bill 1 is $20 and Bill 2 is $20, options for Bill 3: $5, $10, $20
By going through all the possibilities for each bill, we can systematically list all the combinations. In this case, there are 27 possible combinations.
Here is an organized list of all the possible combinations of bills:
1) $5, $5, $5
2) $5, $5, $10
3) $5, $5, $20
4) $5, $10, $5
5) $5, $10, $10
6) $5, $10, $20
7) $5, $20, $5
8) $5, $20, $10
9) $5, $20, $20
10) $10, $5, $5
11) $10, $5, $10
12) $10, $5, $20
13) $10, $10, $5
14) $10, $10, $10
15) $10, $10, $20
16) $10, $20, $5
17) $10, $20, $10
18) $10, $20, $20
19) $20, $5, $5
20) $20, $5, $10
21) $20, $5, $20
22) $20, $10, $5
23) $20, $10, $10
24) $20, $10, $20
25) $20, $20, $5
26) $20, $20, $10
27) $20, $20, $20
Therefore, there are 27 possible combinations of bills Jordan can have in her wallet.
To determine all the possible combinations of bills in Jordan's wallet, we need to consider the different types of bills she might have: $5, $10, and $20. Since Jordan has three bills, let's create an organized list to show all the possible combinations:
1) $5 bill, $5 bill, $5 bill
2) $5 bill, $5 bill, $10 bill
3) $5 bill, $5 bill, $20 bill
4) $5 bill, $10 bill, $5 bill
5) $5 bill, $10 bill, $10 bill
6) $5 bill, $10 bill, $20 bill
7) $5 bill, $20 bill, $5 bill
8) $5 bill, $20 bill, $10 bill
9) $5 bill, $20 bill, $20 bill
10) $10 bill, $5 bill, $5 bill
11) $10 bill, $5 bill, $10 bill
12) $10 bill, $5 bill, $20 bill
13) $10 bill, $10 bill, $5 bill
14) $10 bill, $10 bill, $10 bill
15) $10 bill, $10 bill, $20 bill
16) $10 bill, $20 bill, $5 bill
17) $10 bill, $20 bill, $10 bill
18) $10 bill, $20 bill, $20 bill
19) $20 bill, $5 bill, $5 bill
20) $20 bill, $5 bill, $10 bill
21) $20 bill, $5 bill, $20 bill
22) $20 bill, $10 bill, $5 bill
23) $20 bill, $10 bill, $10 bill
24) $20 bill, $10 bill, $20 bill
25) $20 bill, $20 bill, $5 bill
26) $20 bill, $20 bill, $10 bill
27) $20 bill, $20 bill, $20 bill
So, there are 27 possible combinations of bills in Jordan's wallet.