A carnival game gives variety bags as prizes. The game operator uses 100 balloons and 68 stickers to put into a certain number of bags. How many balloons and how many stickers can go in each bag if they make the greatest number of bags possible so that each bag has the same number of balloons and the same number of stickers?(1 point)
Responses
50 balloons and 34 stickers
50 balloons and 34 stickers
4 balloons and 4 stickers
4 balloons and 4 stickers
25 balloons and 17 stickers
25 balloons and 17 stickers
17 balloons and 25 stickers
17 balloons and 25 stickers
To find out how many balloons and stickers can go in each bag, we need to find the greatest common divisor (GCD) of the given numbers, which are 100 and 68.
The GCD of 100 and 68 is 4.
Therefore, the greatest number of bags possible is when each bag contains 4 balloons and 4 stickers.