A gaseous product of a reaction is collected at 280K and 0.95 atm. Given R=0.0821L⋅atmmol⋅K
, what is the molar mass of the gas, in grams per mole, if 5.49 g of gas occupies 4.92 L?(1 point)
Responses
24 g/mol
24 g/mol
0.04 g/mol
0.04 g/mol
133 g/mol
133 g/mol
27 g/mol
To solve this problem, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in L)
n = number of moles of gas
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in K)
We can calculate the number of moles of gas using the given information:
n = PV / RT
n = (0.95 atm * 4.92 L) / (0.0821 L·atm/mol·K * 280 K)
n = 0.217 mol
To find the molar mass of the gas, we can use the formula:
molar mass = mass / moles
We are given that the mass is 5.49 g and the number of moles is 0.217 mol, so we can calculate:
molar mass = 5.49 g / 0.217 mol
molar mass ≈ 25.35 g/mol
Therefore, the molar mass of the gas is 25.35 g/mol.
To find the molar mass of the gas, we can use the ideal gas law equation, which is:
PV = nRT
Where:
P = Pressure of the gas (0.95 atm)
V = Volume of the gas (4.92 L)
n = Number of moles of the gas (unknown)
R = Ideal gas constant (0.0821 L⋅atm/mol⋅K)
T = Temperature of the gas in Kelvin (280K)
Rearranging the equation to solve for n, we get:
n = PV / RT
Substituting the given values, we have:
n = (0.95 atm) * (4.92 L) / (0.0821 L⋅atm/mol⋅K) * (280 K)
Calculating the result, we find:
n ≈ 0.222 mol
Next, we can calculate the molar mass of the gas by dividing the mass of the gas (5.49 g) by the number of moles (0.222 mol):
Molar mass = Mass / Moles
Molar mass = 5.49 g / 0.222 mol
Calculating the result, we find:
Molar mass ≈ 24.7 g/mol
Therefore, the molar mass of the gas is approximately 24.7 g/mol.