CaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3
) in the chemical reaction shown. What is the total mass of the products?
To find the total mass of the products, we need to determine the molar mass of each compound involved in the reaction.
The molar mass of CaCO3 (calcium carbonate) is:
1 calcium (Ca) atom with a molar mass of 40.08 g/mol
1 carbon (C) atom with a molar mass of 12.01 g/mol
3 oxygen (O) atoms with a molar mass of 16.00 g/mol each
Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + (16.00 g/mol x 3) = 100.09 g/mol
According to the balanced chemical equation, 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO. Therefore, the molar mass of the products can be calculated as follows:
Molar mass of CO2 = 12.01 g/mol + (16.00 g/mol x 2) = 44.01 g/mol
Molar mass of CaO = 40.08 g/mol + 16.00 g/mol = 56.08 g/mol
Now, we need to find the number of moles of CaCO3 in 30 grams:
Number of moles = Mass / Molar mass
Number of moles of CaCO3 = 30 g / 100.09 g/mol = 0.2996 mol (approx.)
Since the molar ratio of CaCO3 to CO2 and CaO is 1:1, the number of moles of CO2 and CaO produced will also be 0.2996 mol each.
To find the mass of each product, we can multiply the number of moles by their respective molar masses:
Mass of CO2 = 0.2996 mol x 44.01 g/mol = 13.2 g (approx.)
Mass of CaO = 0.2996 mol x 56.08 g/mol = 16.8 g (approx.)
Therefore, the total mass of the products is approximately 13.2 g + 16.8 g = 30 g.
To determine the total mass of the products in the given chemical reaction, we need to calculate the molar masses of both carbon dioxide (CO2) and calcium oxide (CaO).
1. Carbon dioxide (CO2):
The molar mass of carbon (C) is approximately 12.01 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. Since there are two oxygen atoms in carbon dioxide, we multiply the molar mass of oxygen by 2.
Molar mass of carbon dioxide (CO2) = (12.01 g/mol) + (16.00 g/mol × 2) = 44.01 g/mol.
2. Calcium oxide (CaO):
The molar mass of calcium (Ca) is approximately 40.08 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. Therefore, the molar mass of calcium oxide (CaO) is:
Molar mass of calcium oxide (CaO) = (40.08 g/mol) + (16.00 g/mol) = 56.08 g/mol.
Now, let's calculate the total mass of the products. The chemical equation states that 1 mole of calcium carbonate (CaCO3) produces 1 mole of carbon dioxide (CO2) and 1 mole of calcium oxide (CaO).
Given that we have 30 grams of calcium carbonate (CaCO3), we can calculate the number of moles using its molar mass:
Number of moles of calcium carbonate (CaCO3) = Mass / Molar mass
= 30 g / 100.09 g/mol (molar mass of calcium carbonate)
= 0.2998 moles (approximately)
Since the stoichiometry of the balanced equation is 1:1:1 for calcium carbonate (CaCO3), carbon dioxide (CO2), and calcium oxide (CaO), the number of moles of carbon dioxide (CO2) and calcium oxide (CaO) will also be 0.2998 each.
Finally, we can calculate the mass of the products:
Mass of carbon dioxide (CO2) = Molar mass of carbon dioxide (CO2) × Number of moles
= 44.01 g/mol × 0.2998 moles
≈ 13.2 grams
Mass of calcium oxide (CaO) = Molar mass of calcium oxide (CaO) × Number of moles
= 56.08 g/mol × 0.2998 moles
≈ 16.8 grams
Therefore, the total mass of the products (carbon dioxide and calcium oxide) is approximately 13.2 grams + 16.8 grams = 30 grams.