A scientist heats 30 grams of calcium carbonate(CaCO3) in the chemical reaction shown. What is the total mass of the products. CaCO3 - CO2 + CaO
To find the total mass of the products, we need to figure out the molar masses of CO2 and CaO.
The molar mass of CO2 is 12.01 g/mol (for C) + 16.00 g/mol (for each O) = 44.01 g/mol.
The molar mass of CaO is 40.08 g/mol (for Ca) + 16.00 g/mol (for O) = 56.08 g/mol.
Since the molar mass of CaCO3 is 40.08 g/mol (for Ca) + 12.01 g/mol (for C) + (16.00 g/mol for each O) = 100.09 g/mol.
We know that the molar mass of CaCO3 is 100.09 g/mol and the molar mass of CO2 is 44.01 g/mol. This means that for every 100.09 g of CaCO3 heated, 44.01 g of CO2 is produced.
Therefore, if 30 g of CaCO3 is heated, the mass of CO2 produced will be (30g / 100.09g/mol) * 44.01g/mol = 13.2 g.
Since the reaction also produces CaO, with a molar mass of 56.08 g/mol, the total mass of the products will be 13.2 g (for CO2) + (30 g / 100.09 g/mol) * 56.08 g/mol = 13.2 g + 16.8 g = 30 g.
So, the total mass of the products in this reaction is 30 grams.
To determine the total mass of the products in the given chemical reaction, we need to balance the equation first:
CaCO3 → CO2 + CaO
The molar mass of calcium carbonate (CaCO3) can be calculated as follows:
CaCO3 = (1 atom of calcium × atomic mass of calcium) + (1 atom of carbon × atomic mass of carbon) + (3 atoms of oxygen × atomic mass of oxygen)
CaCO3 = (1 × 40.08 g/mol) + (1 × 12.01 g/mol) + (3 × 16.00 g/mol)
CaCO3 = 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
CaCO3 = 100.09 g/mol
Now, let's calculate the mass of carbon dioxide (CO2) produced:
The molar mass of carbon dioxide (CO2) can be calculated as follows:
CO2 = (1 atom of carbon × atomic mass of carbon) + (2 atoms of oxygen × atomic mass of oxygen)
CO2 = (1 × 12.01 g/mol) + (2 × 16.00 g/mol)
CO2 = 12.01 g/mol + 32.00 g/mol
CO2 = 44.01 g/mol
Since the balanced equation shows that 1 mole of calcium carbonate produces 1 mole of carbon dioxide, we can calculate the mass of carbon dioxide produced using the given mass of calcium carbonate:
Mass of CO2 = (Mass of CaCO3 × molar mass of CO2) / molar mass of CaCO3
Mass of CO2 = (30 g × 44.01 g/mol) / 100.09 g/mol
Mass of CO2 = 1320.3 g / 100.09 g/mol
Mass of CO2 ≈ 13.20 g
Similarly, the molar mass of calcium oxide (CaO) can be calculated as follows:
CaO = (1 atom of calcium × atomic mass of calcium) + (1 atom of oxygen × atomic mass of oxygen)
CaO = (1 × 40.08 g/mol) + (1 × 16.00 g/mol)
CaO = 40.08 g/mol + 16.00 g/mol
CaO = 56.08 g/mol
Again, since the balanced equation shows that 1 mole of calcium carbonate produces 1 mole of calcium oxide, we can calculate the mass of calcium oxide produced using the given mass of calcium carbonate:
Mass of CaO = (Mass of CaCO3 × molar mass of CaO) / molar mass of CaCO3
Mass of CaO = (30 g × 56.08 g/mol) / 100.09 g/mol
Mass of CaO = 1682.4 g / 100.09 g/mol
Mass of CaO ≈ 16.82 g
Therefore, the total mass of the products, carbon dioxide (CO2) and calcium oxide (CaO), is approximately 13.20 g + 16.82 g = 29.02 g.
To determine the total mass of the products in the given chemical reaction, we first need to calculate the molar masses of each compound involved.
The molar mass of calcium carbonate (CaCO3) can be calculated by summing the atomic masses of its constituent elements.
- The atomic mass of calcium (Ca) is approximately 40.08 g/mol.
- The atomic mass of carbon (C) is approximately 12.01 g/mol.
- The atomic mass of oxygen (O) is approximately 16.00 g/mol.
The molar mass of CaCO3 is therefore:
(1 * 40.08) + (1 * 12.01) + (3 * 16.00) = 100.09 g/mol
Now, let's calculate the molar masses of the products.
- Carbon dioxide (CO2):
The atomic mass of carbon (C) is approximately 12.01 g/mol.
The atomic mass of oxygen (O) is approximately 16.00 g/mol.
The molar mass of CO2 is therefore: (1 * 12.01) + (2 * 16.00) = 44.01 g/mol
- Calcium oxide (CaO):
The atomic mass of calcium (Ca) is approximately 40.08 g/mol.
The atomic mass of oxygen (O) is approximately 16.00 g/mol.
The molar mass of CaO is therefore: 40.08 + 16.00 = 56.08 g/mol
Now we can calculate the moles of calcium carbonate (CaCO3) by dividing the mass (30 grams) by the molar mass (100.09 g/mol):
30 g / 100.09 g/mol = 0.2997 mol (rounded to 4 decimal places)
Since the stoichiometry of the reaction shows that 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO, we can conclude that the total moles of products will be the same, which is 0.2997 mol.
Finally, let's determine the total mass of the products.
Mass of CO2 = moles of CO2 * molar mass of CO2 = 0.2997 mol * 44.01 g/mol = 13.199 grams
Mass of CaO = moles of CaO * molar mass of CaO = 0.2997 mol * 56.08 g/mol = 16.801 grams
Therefore, the total mass of the products is 13.199 grams + 16.801 grams = 30 grams.