Maria and Jose are 53 years total. Maria is 11 years more than half Jose’s age. How old is Maria?
Let's say Jose's age is x.
Half of Jose's age is x/2
Maria is 11 years more than half of Jose's age, meaning Maria is (x/2)+11 years old.
The total age of Maria and Jose is 53 years, so (x/2)+11+x=53.
Combining like terms, we get (3/2)x + 11 = 53.
Subtracting 11 from both sides gives (3/2)x = 42.
To isolate x, we multiply both sides by 2/3: x = (2/3)*42 = 28.
Therefore, Maria's age is (28/2)+11 = 14+11 = <<(28/2) + 11=25>>25 years old. Answer: \boxed{25}.
Let's break down the information given step-by-step:
Step 1: Let's represent Maria's age as M and Jose's age as J.
Step 2: We know that Maria and Jose's ages sum up to 53 years:
M + J = 53
Step 3: Maria's age is 11 years more than half of Jose's age:
M = (1/2)J + 11
Now, we can solve this system of equations to find the values of M and J.
Step 4: Substitute the value of M from the second equation into the first equation:
((1/2)J + 11) + J = 53
Step 5: Combine like terms:
(3/2)J + 11 = 53
Step 6: Subtract 11 from both sides of the equation:
(3/2)J = 42
Step 7: Multiply both sides of the equation by 2/3:
J = 28
Step 8: Substitute the value of J back into the second equation to find Maria's age:
M = (1/2)(28) + 11
M = 14 + 11
M = 25
Therefore, Maria is 25 years old.