Two machines at a factory are filling cans of soup one machine has already filled up 180 cans at a rate of 15 per min the second machine has already filled 210 cans of soup and fills cans at a rate of 12 per min write an equation that show when both machines have fill the same amount of drinks
Let's assume the time (in minutes) it takes for both machines to fill the same amount of cans is represented by "t".
The number of cans filled by the first machine is given by 15t (rate of filling multiplied by time).
The number of cans filled by the second machine is given by 12t.
Since both machines have filled the same amount of cans, we can set up the equation:
15t = 12t
Let's denote the number of minutes as 't'.
The first machine fills cans at a rate of 15 per minute and has already filled 180 cans. Therefore, the number of cans filled by the first machine after 't' minutes can be represented as:
Number of cans filled by the first machine = 180 + 15t
The second machine fills cans at a rate of 12 per minute and has already filled 210 cans. Therefore, the number of cans filled by the second machine after 't' minutes can be represented as:
Number of cans filled by the second machine = 210 + 12t
To find the point in time when both machines have filled the same amount of cans, we can equate these two expressions:
180 + 15t = 210 + 12t
Simplifying the equation will give us the answer.