What is the least integer whose square root is in irrational number between 5 and 7 26 13 25 or 6
The square root of 26 is approximately 5.1, which is between 5 and 7. Therefore, the least integer whose square root is between 5 and 7 is 26.
To find the least integer whose square root is between 5 and 7, we need to determine the perfect squares near 5 and 7. The perfect square nearest to 5 is 4 (2^2), and the perfect square nearest to 7 is 9 (3^2).
Now, we need to find the integers between 2 and 3. The only integer between 2 and 3 is 3 itself. Therefore, 3 is the least integer whose square root is an irrational number between 5 and 7.