A forklift lifts a 900-Newton load 5 meters high. It then carries this load to a horizontal distance of 20 meters. Determine the total work done on the load.
4,500 Joules
9,000 Joules
17,640 Joules
18,000 Joules
27,000 Joules
The work done on an object is given by the equation:
Work = Force * Distance * cos(theta)
Where:
- Force is the magnitude of the force applied to the object (in newtons)
- Distance is the distance over which the force is applied (in meters)
- theta is the angle between the force vector and the displacement vector (in degrees)
In this case, the forklift lifts the load vertically, so theta = 0 degrees (since the force vector is parallel to the displacement vector).
Work = 900 N * 5 m * cos(0 degrees)
Work = 900 N * 5 m * 1
Work = 4,500 Joules
Therefore, the total work done on the load is 4,500 Joules.
To determine the total work done on the load, we need to calculate the work done in lifting the load and the work done in carrying the load horizontally.
First, let's calculate the work done in lifting the load. The work done is given by the formula:
Work = Force x Distance
So, the work done in lifting the load is:
Work = 900 N x 5 m = 4500 J
Next, let's calculate the work done in carrying the load horizontally. Since the horizontal distance is 20 meters and the force exerted in the horizontal direction is perpendicular to the displacement, no work is done in carrying the load horizontally.
Therefore, the total work done on the load is:
Total Work = Work lifting + Work carrying = 4500 J + 0 J = 4500 J
So, the total work done on the load is 4500 Joules.
Hence, the correct answer is:
4500 Joules