A forklift lifts a 900-Newton load 5 meters high. It then carries this load to a horizontal distance of 20 meters. Determine the total work done on the load.
The work done on an object is equal to the force applied on it multiplied by the distance it is moved.
The work done to lift the load to a height of 5 meters is given by the equation work = force * distance:
work = 900 N * 5 m = 4500 Joules
The work done to carry the load horizontally for 20 meters is also given by the equation work = force * distance:
work = 900 N * 20 m = 18000 Joules
Therefore, the total work done on the load is 4500 Joules + 18000 Joules = 22500 Joules.
To determine the total work done on the load, we need to calculate the work done in raising the load vertically and the work done in moving the load horizontally.
First, let's calculate the work done in raising the load vertically:
Work = force × distance × cos(theta)
where force is the weight of the load, distance is the vertical distance lifted, and theta is the angle between the force and the direction of motion (which is 0 degrees in this case since the force is vertically upward).
So, in this case, the force is the weight of the load, which is given as 900 Newtons, and the distance lifted is 5 meters.
Work = 900 N × 5 m × cos(0°) = 4500 Joules
Next, let's calculate the work done in moving the load horizontally:
Work = force × distance × cos(theta)
In this case, the force is the same as the weight of the load, which is 900 Newtons, and the distance moved horizontally is 20 meters. However, in this case, theta is 90 degrees since the force is acting horizontally.
Work = 900 N × 20 m × cos(90°) = 0 Joules
Since the cosine of 90 degrees is 0, the work done in moving the load horizontally is 0.
Therefore, the total work done on the load is the sum of the work done vertically and horizontally:
Total Work = Work vertically + Work horizontally
= 4500 Joules + 0 Joules
= 4500 Joules
So, the total work done on the load is 4500 Joules.
To determine the total work done on the load, we need to calculate the work done while lifting the load vertically and the work done while carrying the load horizontally.
1. Work done while lifting the load:
The formula for calculating work is W = F * d * cos(theta), where W is the work done, F is the force applied, d is the distance moved, and theta is the angle between the force and the direction of motion.
In this case, the force applied is 900 Newton, and the distance moved vertically (height) is 5 meters.
The angle between the force and the direction of motion (vertical direction) is 0 degrees, as the force is applied vertically upwards.
Therefore, the work done while lifting the load is:
W1 = F * d * cos(theta)
= 900 N * 5 m * cos(0 degrees)
= 4500 joules
2. Work done while carrying the load horizontally:
Since the load is being carried horizontally, there is no vertical displacement, and therefore, no work is done in the vertical direction.
The force of 900 Newtons is applied horizontally, and the distance moved is 20 meters.
The angle between the force and the direction of motion (horizontal direction) is 0 degrees, as the force is applied horizontally.
Therefore, the work done while carrying the load horizontally is:
W2 = F * d * cos(theta)
= 900 N * 20 m * cos(0 degrees)
= 18000 joules
To calculate the total work done on the load, we add the work done while lifting the load (W1) to the work done while carrying the load horizontally (W2):
Total work done = W1 + W2
= 4500 joules + 18000 joules
= 22500 joules
Therefore, the total work done on the load is 22500 joules.