Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.(4 points)
To find the change in temperature during these three hours, we need to subtract the initial temperature from the final temperature.
Change in temperature = Final temperature - Initial temperature
Let's calculate the change in temperature:
Change in temperature = (-1.6°C) - (-5.8°C)
Change in temperature = -1.6°C + 5.8°C
Change in temperature = 4.2°C
The change in temperature during these three hours is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.
To find the change in temperature during these three hours, we need to subtract the temperature at 9 a.m. from the temperature at noon.
Let's denote the temperature at 9 a.m. as T1 and the temperature at noon as T2.
T1 = −5.8 degrees Celsius
T2 = −1.6 degrees Celsius
The equation to find the change in temperature is: Change in temperature = T2 - T1
Substituting the given values into the equation, we get:
Change in temperature = (-1.6) - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius.
The answer, 4.2 degrees Celsius, represents the change in temperature from 9 a.m. to noon. In this case, the temperature increased by 4.2 degrees Celsius during these three hours.