Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.

To find the change in temperature, we need to subtract the initial temperature from the final temperature.

Final temperature: -1.6 degrees Celsius
Initial temperature: -5.8 degrees Celsius

Change in temperature = Final temperature - Initial temperature
Change in temperature = (-1.6) - (-5.8)

To simplify, we can change the subtraction of two negative numbers to addition, and so:
Change in temperature = (-1.6) + 5.8

Adding the numbers, we get:
Change in temperature = 4.2 degrees Celsius

The change in temperature during these three hours is 4.2 degrees Celsius.

This means that the temperature increased by 4.2 degrees Celsius between 9 a.m. and noon.

did u explain what the answer means

Apologies for the oversight. The answer, 4.2 degrees Celsius, represents the change in temperature during the three-hour period from 9 a.m. to noon. More specifically, it indicates the increase in temperature from -5.8 degrees Celsius at 9 a.m. to -1.6 degrees Celsius at noon. The positive value of the change in temperature indicates a rise in temperature. Therefore, the air temperature increased by 4.2 degrees Celsius over the span of three hours.

To find the change in temperature during these three hours, we need to subtract the initial temperature from the final temperature.

Initial temperature: -5.8 degrees Celsius
Final temperature: -1.6 degrees Celsius

Change in temperature = Final temperature - Initial temperature
Change in temperature = (-1.6) - (-5.8)

To subtract a negative number, we can change the sign and add the numbers:
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius

The change in temperature during these three hours is 4.2 degrees Celsius.

This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.