Solve the following word problem the air temperature at 9 AM is -5.8°C. The air temperature at noon is -1.6°C. What is the change in the temperature during these three hours right and solve an equation to show your answer, then explain what your answer mean.
To find the change in temperature during these three hours, we can subtract the temperature at 9 AM from the temperature at noon.
Change in temperature = Temperature at noon - Temperature at 9 AM
Change in temperature = (-1.6°C) - (-5.8°C)
Change in temperature = -1.6°C + 5.8°C
Change in temperature = 4.2°C
So, the change in temperature during these three hours is 4.2°C.
This solution means that there was an increase in temperature of 4.2 degrees Celsius from 9 AM to noon. The temperature increased by 4.2°C.
To find the change in temperature during these three hours, we can subtract the initial temperature at 9 AM from the temperature at noon.
Let's denote the initial temperature at 9 AM as T1 and the temperature at noon as T2.
T1 = -5.8°C (temperature at 9 AM)
T2 = -1.6°C (temperature at noon)
The change in temperature can be calculated by subtracting T1 from T2:
Change in temperature = T2 - T1 = (-1.6°C) - (-5.8°C) = -1.6°C + 5.8°C = 4.2°C.
Therefore, the change in temperature during these three hours is 4.2°C.
In equation form:
Change in temperature = T2 - T1 = -1.6°C - (-5.8°C) = -1.6°C + 5.8°C = 4.2°C.
This means that the temperature increased by 4.2 degrees Celsius during the three hours from 9 AM to noon.