Find the numerical equivalent of 2^5 ⋅2^−2
To find the numerical equivalent of 2^5 ⋅ 2^−2, we can simplify the expression by using the property of exponents, which states that when we multiply two numbers with the same base, we add their exponents.
2^5 ⋅ 2^−2 can be rewritten as 2^(5 + (-2)).
The exponent 5 + (-2) equals 3.
Therefore, the numerical equivalent of 2^5 ⋅ 2^−2 is 2^3, which simplifies to 8.
To find the numerical equivalent, we can simplify the expression using the rules of exponents.
First, we can apply the rule that states when multiplying two numbers with the same base, we add their exponents.
So, 2^5 ⋅ 2^(-2) = 2^(5 + (-2)) = 2^3.
Then, we simplify using the rule that says when raising a number to a positive exponent, we multiply the base by itself that many times.
In this case, 2^3 = 2 × 2 × 2 = 8.
Therefore, the numerical equivalent of 2^5 ⋅ 2^(-2) is 8.
To find the numerical equivalent of 2^5 ⋅ 2^−2, we need to understand the properties of exponents. When you multiply two numbers with the same base, you add their exponents. In this case, the base is 2.
First, let's simplify the expression by adding the exponents:
2^5 ⋅ 2^−2 = 2^(5 + -2)
Next, we add the exponents:
5 + -2 = 3
So, 2^5 ⋅ 2^−2 is equivalent to 2^3.
Now we can find the numerical value of 2^3 by evaluating the expression:
2^3 = 2 × 2 × 2 = 8
Therefore, the numerical equivalent of 2^5 ⋅ 2^−2 is 8.