Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means. Don't plagarize.
To find the change in temperature during these three hours, we can subtract the initial temperature from the final temperature.
Let's assign the initial temperature at 9 a.m. as T1, and the temperature at noon as T2.
T1 = -5.8 degrees Celsius
T2 = -1.6 degrees Celsius
Change in temperature = T2 - T1
Change in temperature = (-1.6) - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius
The change in temperature during these three hours is 4.2 degrees Celsius. This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.
To find the change in temperature during the three hours, we can subtract the air temperature at 9 a.m. from the temperature at noon.
Temperature at noon = -1.6 degrees Celsius
Temperature at 9 a.m. = -5.8 degrees Celsius
Change in temperature = Temperature at noon - Temperature at 9 a.m.
Change in temperature = -1.6 - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius
The change in temperature during these three hours is 4.2 degrees Celsius. This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.