Solve the following word problem the air temperature at 9 AM is -5.8°C. Is there a temperature at noon is -1.6°C. What is the changing the temperature during these three hours right and solve an equation to show your answer, then explain your answer means.
To find the change in temperature during the three hours from 9 AM to noon, we need to subtract the initial temperature from the final temperature.
The initial temperature at 9 AM is -5.8°C, and the final temperature at noon is -1.6°C. Subtracting the initial temperature from the final temperature gives us:
-1.6°C - (-5.8°C) = -1.6°C + 5.8°C = 4.2°C
So, the change in temperature during these three hours is 4.2°C.
The equation to represent this change in temperature is:
Final temperature - Initial temperature = Change in temperature
Let T be the final temperature, T0 be the initial temperature, and ΔT be the change in temperature. The equation becomes:
T - T0 = ΔT
In this case, T = -1.6°C, T0 = -5.8°C, and ΔT = 4.2°C.
Substituting these values into the equation, we have:
-1.6°C - (-5.8°C) = 4.2°C
Simplifying the equation further, we get:
-1.6°C + 5.8°C = 4.2°C
Therefore, the equation -1.6°C + 5.8°C = 4.2°C represents the change in temperature during the three hours from 9 AM to noon. It means that the temperature increased by 4.2°C during that time period.
To find the temperature change from 9 AM to noon, we can subtract the temperature at 9 AM from the temperature at noon.
Temperature at 9 AM = -5.8°C
Temperature at noon = -1.6°C
Temperature change = (-1.6) - (-5.8)
= -1.6 + 5.8
= 4.2°C
Therefore, the temperature changed by 4.2°C during these three hours.
Mathematically, we can represent this as:
Temperature change = Temperature at noon - Temperature at 9 AM
In this case, temperature change = -1.6 - (-5.8)
= -1.6 + 5.8
= 4.2°C
This means that the temperature increased by 4.2°C from 9 AM to noon.