What is the least integer whose square root is an irrational number between 5 and 7?(1 point)
Responses
26
13
25
6
13
To find the least integer whose square root is an irrational number between 5 and 7, we need to determine the integers that satisfy this condition.
First, we can calculate the square roots of the given integers:
√25 = 5
√36 = 6
√49 = 7
Since 6 is the largest integer whose square root is less than 7, 6 is not an option.
Therefore, the correct answer is 25. The square root of 25 is √25 = 5, which is an irrational number between 5 and 7.
So, the least integer whose square root is an irrational number between 5 and 7 is 25.