A submarine was at a depth of 106.3 feet below sea level. After 5 hours, the submarine was at 481.2 feet below sea level. How far did the submarine travel?
To find out how far the submarine traveled, we need to calculate the difference in depth between the initial depth and the final depth.
The initial depth of the submarine is 106.3 feet below sea level.
The final depth of the submarine is 481.2 feet below sea level.
The difference in depth is 481.2 - 106.3 = <<481.2-106.3=374.9>>374.9 feet.
Therefore, the submarine traveled a distance of 374.9 feet. Answer: \boxed{374.9}.
To find how far the submarine traveled, we need to find the difference between its initial depth and its final depth.
The initial depth was 106.3 feet below sea level, and the final depth was 481.2 feet below sea level.
To find the difference, we subtract the initial depth from the final depth:
481.2 - 106.3 = 374.9 feet
Therefore, the submarine traveled a distance of 374.9 feet.