In 2n7000 MOSFET switching operation. Given VG=0V, R1=95Ω and RDS(on) is 4Ω. Determine the voltage at the drain, VD.
Express your answer in mA and in 2 decimal places.
Vg is gate
In the given circuit, the drain current (ID) through the MOSFET can be determined using Ohm's Law:
ID = (VG - VD) / RD
Where:
ID is the drain current
VG is the gate voltage
VD is the drain voltage
RD is the drain resistor
Given VG = 0V, R1 = 95Ω and RDS(on) = 4Ω, we can calculate ID as follows:
ID = (0 - VD) / (95 + 4)
ID = -VD / 99
We know that RDS(on) is the drain-source resistance when the MOSFET is fully ON. Therefore, when the MOSFET is fully ON, the drain current will be at its maximum value.
The maximum drain current can be calculated using the formula:
ID(max) = (VG - VD) / RDS(on)
Since VG = 0V, we have:
ID(max) = -VD / RDS(on)
ID(max) = -VD / 4
Since we want to find VD, we set ID = ID(max) and solve for VD:
-VD / 99 = -VD / 4
Multiply both sides by 99 and 4 to get rid of the fractions:
4 * -VD = 99 * -VD
-4VD = -99VD
Subtract 99VD from both sides and simplify:
-4VD + 99VD = 0
95VD = 0
Divide both sides by 95:
VD = 0V
Therefore, the voltage at the drain (VD) is 0V.
To determine the voltage at the drain, VD, in a 2n7000 MOSFET switching operation, we can use Ohm's law. Since the gate voltage, VG, is given as 0V, the MOSFET is turned off, and no current flows through it.
To find the voltage at the drain, VD, we need to analyze the circuit. Assuming the MOSFET is off, we can ignore the RDS(on) value.
To calculate VD, we can use the following formula:
VD = VG - (IR1)
Let's substitute the given values into the formula:
VD = 0V - (IR1)
Let's solve for VD. First, we need to find the current, I.
Using Ohm's law, we can calculate the current through the resistor by dividing the voltage across it by its resistance:
I = (VG - VD) / R1
Since VG is 0V, the equation becomes:
I = -VD / R1
To solve for VD, we rearrange the formula:
VD = -IR1
Now let's calculate VD. The current, I, is determined by the voltage across the resistor, which is 0V since the MOSFET is off:
VD = -(0V) * 95Ω
VD = 0V
Therefore, the voltage at the drain, VD, is 0V.