The resistance in a circuit is halved. What happens to the voltage?
V=IR
(1 point)
Responses
The voltage remains the same.
The voltage remains the same.
The voltage is doubled.
The voltage is doubled.
The voltage is increased by a factor of 4.
The voltage is increased by a factor of 4.
The voltage is halved.
The voltage is halved.
PLZZZ HURRY
I think that the voltage would be cut in hald=f am i right
Yes, you are correct. The voltage is halved.
You are correct! When the resistance in a circuit is halved, according to Ohm's Law (V = IR), the voltage will also be halved. So, if the initial voltage was V, after halving the resistance, the new voltage would be V/2.
To understand why this happens, let's break down Ohm's Law:
V = IR
V: voltage (in volts)
I: current (in amperes)
R: resistance (in ohms)
Ohm's Law states that the voltage across a circuit element is equal to the current flowing through it multiplied by the resistance. So, if we decrease the resistance, the voltage must decrease proportionally in order to maintain the same current.
In this case, when the resistance is halved, the current flowing through the circuit would double (assuming the applied voltage remains constant), but the voltage would be halved in order to keep the product of current and resistance constant.
Therefore, halving the resistance in a circuit will result in the voltage being halved as well.