The kinetic energy of a 25-gram bullet traveling at 500 m/s is?
To calculate the kinetic energy of an object, you can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given:
Mass = 25 grams = 0.025 kg (since 1 kg = 1000 grams)
Velocity = 500 m/s
Now substituting the values in the formula,
Kinetic Energy = (1/2) * 0.025 * (500)^2
Kinetic Energy = 0.5 * 0.025 * 250000
Kinetic Energy = 3125 Joules
Therefore, the kinetic energy of a 25-gram bullet traveling at 500 m/s is 3125 Joules.
To calculate the kinetic energy of the bullet, you can use the following formula:
Kinetic Energy (KE) = (1/2) * mass * velocity^2
Given:
Mass of the bullet (m) = 25 grams = 0.025 kg
Velocity of the bullet (v) = 500 m/s
Using the formula:
KE = (1/2) * 0.025 * (500^2)
First, square the velocity:
KE = (1/2) * 0.025 * 250000
Next, multiply the mass and the squared velocity:
KE = 3125 joules
So, the kinetic energy of a 25-gram bullet traveling at 500 m/s is 3125 joules.