The speed of a bullet of mass 10g is 720km\h.calculate the kinetic energy of the bullet in joules
Solve it for me
To calculate the kinetic energy of the bullet, we need to use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
First, we need to convert the mass of the bullet from grams to kilograms:
1 gram = 0.001 kilograms
Therefore, mass = 10 grams * 0.001 kg/gram = 0.01 kg
Next, we need to convert the velocity of the bullet from km/h to m/s:
1 km = 1000 m
1 hour = 3600 seconds
Therefore, velocity = 720 km/h * (1000 m/1 km) * (1 h/3600 s) = 200 m/s
Now, we can substitute the values into the formula:
Kinetic Energy = (1/2) * 0.01 kg * (200 m/s)^2
Simplifying,
Kinetic Energy = 0.005 kg * (200 m/s)^2
Kinetic Energy = 0.005 kg * 40,000 m^2/s^2
Kinetic Energy = 200 joules
Therefore, the kinetic energy of the bullet is 200 joules.
To calculate the kinetic energy (KE) of the bullet, we can use the formula:
KE = (1/2) * mass * velocity^2
First, let's convert the mass of the bullet from grams to kilograms.
1 gram = 0.001 kilograms
So, the mass of the bullet is:
10 g = 10 * 0.001 kg = 0.01 kg
Next, let's convert the velocity of the bullet from km/h to m/s.
1 km/h = 0.2778 m/s
So, the velocity of the bullet is:
720 km/h = 720 * 0.2778 m/s = 200.16 m/s (approximately)
Now we can calculate the kinetic energy (KE) using the formula:
KE = (1/2) * mass * velocity^2
= (1/2) * 0.01 kg * (200.16 m/s)^2
= (1/2) * 0.01 kg * 40064.8064 m^2/s^2
= 0.005 * 40064.8064 J
= 200.324032 J
Therefore, the kinetic energy of the bullet is approximately 200.324032 joules.