A survey of a class of 32

students found that 17
students are girls, 11
students participate in clubs, and 10
students both are girls and participate in clubs.

What is the probability that a student participates in clubs, given that the student is a girl?

Responses

1032
10 over 32

1710
17 tenths

1117
11 over 17

10/17

The probability that a student participates in clubs, given that the student is a girl, is 10/17.

A leather store performs an observational survey of women walking through a mall. There were 30

women that walked by in an hour. Of those women, 18
were carrying purses, 12
were wearing belts, and 6
were both carrying purses and wearing belts.

What is the probability that a woman was wearing a belt, given that the woman was also carrying a purse?

Responses

2/5
2 fifths

1/3
1 third

1/2
1 half

1/5

The probability that a woman was wearing a belt, given that the woman was also carrying a purse, is 1/3 or 1 third.

Given the following probabilities, for what P(B)

are events A
and B
independent?
P(A)=12
P(A and B)=16
Responses

1/4
1 fourth

3/4
3 fourths

1/3
1 third

1/8

Events A and B are independent if and only if P(A and B) = P(A) * P(B).

Given that P(A) = 1/2 and P(A and B) = 1/6, let's find the value of P(B):

P(A and B) = P(A) * P(B)
1/6 = 1/2 * P(B)
1/6 = P(B)/2
1/6 * 2 = P(B)
1/3 = P(B)

So the value of P(B) that makes events A and B independent is 1/3 or 1 third.

An experiment consists of rolling a standard six-sided die once. Event A

is "rolling an even number" and event B
is "rolling a 2.{}^{\prime\prime}
Are the events dependent or independent? Why?

Select the option that correctly answers both questions.

Responses

Events A
and B
are dependent, because P(B)≠P(B|A).
Events cap A and cap b are dependent, because P(B)≠P(B|A).

Events A
and B
are independent, because P(A)=P(B|A)=12.
Events cap A and cap b are independent, because

Events A
and B
are independent, because P(B)=P(B|A)=16.
Events cap A and cap b are independent, because

Events A
and B
are dependent, because P(A)≠P(B|A).

Events A and B are dependent because P(B) ≠ P(B|A).