The. total number of atoms in. 8.5 gram of NH3 is.
To calculate the total number of atoms in 8.5 grams of NH3, we first need to determine the number of moles of NH3 in 8.5 grams.
The molar mass of NH3 is 17.03 g/mol (14.01 g/mol for nitrogen + 3.02 g/mol for hydrogen).
So,
moles of NH3 = mass of NH3 / molar mass of NH3
= 8.5 g / 17.03 g/mol
= 0.498 mol
Next, we use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
Number of atoms = moles of NH3 x Avogadro's number
= 0.498 mol x 6.022 x 10^23 atoms/mol
= 2.999 x 10^23 atoms
Therefore, there are approximately 2.999 x 10^23 atoms in 8.5 grams of NH3.
To find the total number of atoms in 8.5 grams of NH3 (ammonia), we need to use the concept of moles and Avogadro's number.
Step 1: Calculate the molar mass of NH3.
- Look up the atomic masses of nitrogen (N) and hydrogen (H) from the periodic table.
- Nitrogen (N) has an atomic mass of approximately 14.01 g/mol.
- Hydrogen (H) has an atomic mass of approximately 1.01 g/mol.
- Since NH3 consists of one nitrogen atom and three hydrogen atoms, we can calculate the molar mass as follows:
Molar mass of NH3 = (1 * atomic mass of N) + (3 * atomic mass of H)
Molar mass of NH3 = (1 * 14.01 g/mol) + (3 * 1.01 g/mol)
Molar mass of NH3 = 17.03 g/mol
Step 2: Calculate the number of moles in 8.5 grams of NH3.
- We can use the formula:
Number of moles = given mass / molar mass
Number of moles = 8.5 g / 17.03 g/mol
Number of moles = 0.498 mol (rounded to three decimal places)
Step 3: Calculate the number of atoms in 0.498 moles of NH3.
- One mole of any substance contains Avogadro's number of particles, which is approximately 6.022 × 10^23.
- Therefore, we can use the formula:
Number of atoms = number of moles * Avogadro's number
Number of atoms = 0.498 mol * 6.022 × 10^23 atoms/mol
Number of atoms ≈ 2.997 × 10^23 atoms
Thus, the total number of atoms in 8.5 grams of NH3 is approximately 2.997 × 10^23 atoms.