An pyramid is displayed with the height of 6 yd base yd and radius 11 yd
what is the volume of the pyramid to the nearest while unit?
99 yd^3
132 yd^3
198 yd^3
396 yd^3
We can use the formula for the volume of a pyramid: V = (1/3)Bh, where B is the area of the base and h is the height.
First, we need to find the area of the base. Since the base is circular, we can use the formula for the area of a circle: A = πr^2, where r is the radius.
A = π(11 yd)^2 = 121π yd^2 (rounded to the nearest whole number, this is approximately 380 yd^2)
Now we can plug in the values we have:
V = (1/3)(121π yd^2)(6 yd)
V ≈ 396 yd^3
So the answer is 396 yd^3 (rounded to the nearest whole number).
To find the volume of a pyramid, you can use the formula:
Volume = (1/3) * base area * height
In this case, the height is given as 6 yards and the base is a circle with a radius of 11 yards.
The formula for the area of a circle is:
Area = π * radius^2
Substituting the values into the formulas:
Base area = π * (11 yd)^2
= π * 121 yd^2
= 121π yd^2
Volume = (1/3) * (121π yd^2) * 6 yd
= 22π yd^3 * 6 yd
= 132π yd^3
To get the answer to the nearest whole unit, we need to calculate the value of π and round the result to the nearest whole number.
Using π ≈ 3.14:
Volume ≈ 132 * 3.14 yd^3
Volume ≈ 414.48 yd^3
Rounding this to the nearest whole number, we get:
Volume ≈ 414 yd^3
Therefore, the volume of the pyramid, to the nearest whole unit, is 414 yd^3.