What is the amplitude of the output voltage of AD624AD?
V1 = 10mVpk, 1kHz
VCC = 9V
VEE = -9V
The AD624AD is a high precision instrumentation amplifier and the amplitude of its output voltage will depend on the gain setting and the input signal. In order to calculate the output voltage amplitude, we need to know the gain of the amplifier.
Assuming a gain of 1 (no gain), the output voltage will be equal to the input voltage, which is 10mVpk. The amplitude of the output voltage is therefore 10mVpk.
If the gain of the amplifier is set to a value other than 1, the output voltage will be multiplied by the gain. For example, if the gain is set to 10, the output voltage will be 100mVpk.
It is also important to note that the output voltage of the AD624AD can swing between the supply voltages (VCC and VEE) and cannot exceed these limits. If the output voltage exceeds these limits, it will clip and distort the signal.
To determine the amplitude of the output voltage of AD624AD, you need to consider the gain of the amplifier and the input voltage. The AD624AD is a precision, low power, low noise, rail-to-rail input/output instrumentation amplifier.
The gain of the AD624AD can be configured by connecting an external resistor between the gain select pin (GAIN) and the reference pin (REF). By default, with no external resistor connected, the gain is set to 100.
Given the input voltage of V1 = 10mVpk at 1kHz, the output voltage can be calculated using the gain equation:
Vout = (Vin * G)
Where:
- Vout is the output voltage
- Vin is the input voltage
- G is the amplification factor or gain
Since the default gain of the AD624AD is 100, we substitute the values:
Vout = (10mV * 100)
Vout = 1V
Therefore, the amplitude of the output voltage for the given input is 1V.